Answered

Explore Westonci.ca, the premier Q&A site that helps you find precise answers to your questions, no matter the topic. Discover precise answers to your questions from a wide range of experts on our user-friendly Q&A platform. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.

How do you prove:
csc^2@cos^2@ = csc^2@ -1


Sagot :

[tex]cscx=\frac{1}{sinx};\ sin^2x+cos^2x=1\to cos^2x=1-sin^2x\\----------------------------\\\\csc^2xcos^2x=csc^2x-1\\\\L=csc^2xcos^2x=\frac{1}{sin^2x}\cdot cos^2x=\frac{cos^2x}{sin^2x}\\\\R=csc^2x-1=\frac{1}{sin^2x}-1=\frac{1}{sin^2x}-\frac{sin^2}{sin^2x}=\frac{1-sin^2x}{sin^2x}=\frac{cos^2x}{sin^2x}\\\\\boxed{L=R}[/tex]
[tex]LHS\\ \\ ={ cosec }^{ 2 }\theta { cos }^{ 2 }\theta \\ \\ ={ cosec }^{ 2 }\theta \left( 1-{ sin }^{ 2 }\theta \right)[/tex]

[tex]\\ \\ ={ cosec }^{ 2 }\theta -{ cosec }^{ 2 }\theta { sin }^{ 2 }\theta \\ \\ ={ cosec }^{ 2 }\theta -\frac { 1 }{ { sin }^{ 2 }\theta } \cdot { sin }^{ 2 }\theta [/tex]

[tex]\\ \\ ={ cosec }^{ 2 }\theta -1\\ \\ =RHS[/tex]
We hope our answers were helpful. Return anytime for more information and answers to any other questions you may have. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.