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1/3 (n+1)+2=1/6 (3n-5)

Sagot :

[tex]\frac { 1 }{ 3 } \left( n+1 \right) +2=\frac { 1 }{ 6 } \left( 3n-5 \right)[/tex]

[tex]\\ \\ 6\left\{ \frac { 1 }{ 3 } \left( n+1 \right) +2 \right\} =6\cdot \frac { 1 }{ 6 } \left( 3n-5 \right)[/tex]

[tex]\\ \\ 2\left( n+1 \right) +12=3n-5\\ \\ 2n+2+12=3n-5\\ \\ 2+12+5=3n-2n\\ \\ 19=n[/tex]
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