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Sagot :
use the formula for the cone
1/3 times (area of base) times height
so first we want to find the volume of both cones then subtract the volume of the smaller container from the larger one
area of base for both are equal
area of base=area of circle=pi times r^2
radius=diameter/2
diameter=14
radius=14/2
radius=7
pi times 7^2
pi times 49
3.14 times 49=153.86
smaller so 1/3 times 153.86 times 3=smaller cone=153.86 cm^3
larger
so 1/3 times 153.86 times 17=871.873
subtract smaller from larger
871.873-153.86=718.013 cm^3
the volume of water needed is 718.01 cm^3
1/3 times (area of base) times height
so first we want to find the volume of both cones then subtract the volume of the smaller container from the larger one
area of base for both are equal
area of base=area of circle=pi times r^2
radius=diameter/2
diameter=14
radius=14/2
radius=7
pi times 7^2
pi times 49
3.14 times 49=153.86
smaller so 1/3 times 153.86 times 3=smaller cone=153.86 cm^3
larger
so 1/3 times 153.86 times 17=871.873
subtract smaller from larger
871.873-153.86=718.013 cm^3
the volume of water needed is 718.01 cm^3
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