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Sagot :
[tex]y=5x-7 \\
-3x-2y=-12 \\ \\
\hbox{substitute 5x-7 for y in the 2nd equation:} \\
-3x-2(5x-7)=-12 \\
-3x-10x+14=-12 \\
-13x+14=-12 \ \ \ |-14 \\
-13x=-26 \ \ \ |\div (-13) \\
x=2 \\ \\
y=5x-7=5 \times 2-7=10-7=3 \\ \\
\boxed{(x,y)=(2,3)}[/tex]
Since −3x does not contain the variable to solve for, move it to the right-hand side of the equation by adding 3x to both sides.
y=5x−7
−2y=3x−12
Divide each term in the equation by −2.
y=5x−7
y=−3x/2+6
Create a graph to locate the intersection of the equations. The intersection of the system of equations is the solution.
(2,3)
y=5x−7
−2y=3x−12
Divide each term in the equation by −2.
y=5x−7
y=−3x/2+6
Create a graph to locate the intersection of the equations. The intersection of the system of equations is the solution.
(2,3)

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