Answered

Welcome to Westonci.ca, the ultimate question and answer platform. Get expert answers to your questions quickly and accurately. Our Q&A platform provides quick and trustworthy answers to your questions from experienced professionals in different areas of expertise. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

Finding the center and radius by completing the square
4x(sqrd)+4y(sqrd)+4x-16y-19=0

Sagot :

naǫ
[tex](x-h)^2+(y-k)^2=r^2[/tex]
(h,k) - the center
r - the radius

[tex]4x^2+4y^2+4x-16y-19=0 \ \ \ |\div 4 \\ x^2+y^2+x-4y-\frac{19}{4}=0 \\ x^2+x+\frac{1}{4}+y^2-4y+4-\frac{19}{4}-\frac{1}{4}-4=0 \\ (x+\frac{1}{2})^2+(y-2)^2-\frac{20}{4}-4=0 \\ (x+\frac{1}{2})^2+(y-2)^2-5-4=0 \\ (x+\frac{1}{2})^2+(y-2)^2-9=0 \\ (x+\frac{1}{2})^2+(y-2)^2=9 \\ (x+\frac{1}{2})^2+(y-2)^2=3^2[/tex]

The center - [tex](-\frac{1}{2},2)[/tex]
The radius - [tex]3[/tex]
konrad509
[tex] 4x^2+4y^2+4x-16y-19=0 \\ 4x^2+4x+1+4y^2-16y+16-36=0\\ (2x+1)^2+(2y-4)^2=36[/tex]

center - [tex](-1,4)\\ [/tex]
[tex]r=\sqrt{36}=6[/tex]
We appreciate your time. Please revisit us for more reliable answers to any questions you may have. We appreciate your time. Please come back anytime for the latest information and answers to your questions. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.