Westonci.ca is your trusted source for finding answers to all your questions. Ask, explore, and learn with our expert community. Explore thousands of questions and answers from a knowledgeable community of experts on our user-friendly platform. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.
Sagot :
[tex](x-h)^2+(y-k)^2=r^2[/tex]
(h,k) - the center
r - the radius
[tex]4x^2+4y^2+4x-16y-19=0 \ \ \ |\div 4 \\ x^2+y^2+x-4y-\frac{19}{4}=0 \\ x^2+x+\frac{1}{4}+y^2-4y+4-\frac{19}{4}-\frac{1}{4}-4=0 \\ (x+\frac{1}{2})^2+(y-2)^2-\frac{20}{4}-4=0 \\ (x+\frac{1}{2})^2+(y-2)^2-5-4=0 \\ (x+\frac{1}{2})^2+(y-2)^2-9=0 \\ (x+\frac{1}{2})^2+(y-2)^2=9 \\ (x+\frac{1}{2})^2+(y-2)^2=3^2[/tex]
The center - [tex](-\frac{1}{2},2)[/tex]
The radius - [tex]3[/tex]
(h,k) - the center
r - the radius
[tex]4x^2+4y^2+4x-16y-19=0 \ \ \ |\div 4 \\ x^2+y^2+x-4y-\frac{19}{4}=0 \\ x^2+x+\frac{1}{4}+y^2-4y+4-\frac{19}{4}-\frac{1}{4}-4=0 \\ (x+\frac{1}{2})^2+(y-2)^2-\frac{20}{4}-4=0 \\ (x+\frac{1}{2})^2+(y-2)^2-5-4=0 \\ (x+\frac{1}{2})^2+(y-2)^2-9=0 \\ (x+\frac{1}{2})^2+(y-2)^2=9 \\ (x+\frac{1}{2})^2+(y-2)^2=3^2[/tex]
The center - [tex](-\frac{1}{2},2)[/tex]
The radius - [tex]3[/tex]
[tex] 4x^2+4y^2+4x-16y-19=0 \\
4x^2+4x+1+4y^2-16y+16-36=0\\
(2x+1)^2+(2y-4)^2=36[/tex]
center - [tex](-1,4)\\ [/tex]
[tex]r=\sqrt{36}=6[/tex]
center - [tex](-1,4)\\ [/tex]
[tex]r=\sqrt{36}=6[/tex]
Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.