Answered

Discover a wealth of knowledge at Westonci.ca, where experts provide answers to your most pressing questions. Connect with a community of experts ready to help you find accurate solutions to your questions quickly and efficiently. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.

A 62kg rock climber is attached to a rope that is allowing him to hang horizontally with his feet against the wall. The tension in the rope is 710N and the rope makes an angle of 32 degrees with the horizontal. Determine the force exerted by the wall on the climber's feet.

Answer is 710N, Why?

Sagot :

Answer:

F = 645 N

Explanation:

For equilibrium in vertical direction we can make force balance

so we will have

[tex]F_y + Tsin32 = mg[/tex]

[tex]F_y + 710 sin32 = (62\times 9.8)[/tex]

[tex]F_y = 607.6 - 376.2 [/tex]

[tex]F_y = 231.3 N[/tex]

Now for horizontal equilibrium we know that

[tex]F_x = Tcos32[/tex]

[tex]F_x = 710cos32[/tex]

[tex]F_x = 602.11 N[/tex]

now we have net force due to wall given as

[tex]F = \sqrt{F_x^2 + F_y^2}[/tex]

[tex]F = \sqrt{231.3^2 + 602.11^2}[/tex]

[tex]F = 645 N[/tex]

We hope this information was helpful. Feel free to return anytime for more answers to your questions and concerns. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. We're glad you chose Westonci.ca. Revisit us for updated answers from our knowledgeable team.