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Sagot :
The formula for the volume of a cone is π r²h/3. You are given the height and the diametre of the cone. You need the radius which is half the diametre (4). So, f you were to write this out, it would look like this:
3.14 × 4² × 10/3
your answer is going to be 167 cm³
3.14 × 4² × 10/3
your answer is going to be 167 cm³
Ok.
The volume of a cone is the volume of a cylinder over 3.
The volume of a cone is:
[tex] \frac{1}{3} \pi r^{2}h[/tex]
This problem gives us the diameter, which is twice of the radius. So, we'll just half it.
Radius (me) = 4 cm.
Substitute our given values into the equation.
[tex] \frac{1}{3} \pi (4)^{2}h \ or \ \frac{1}{3} \pi (4)^{2}(10) \ or \ \frac{1}{3} \pi (16)(10)[/tex]
Multiply
[tex] \frac{1}{3} \pi(160) \ or \ \frac{1}{3} (3.14)(160) \ or \ 1.047(160)[/tex]
Multiply
[tex]167.52 \ cm^{3}[/tex]
This would make [tex]167 \ cm^{3} [/tex] the closest option.
The volume of a cone is the volume of a cylinder over 3.
The volume of a cone is:
[tex] \frac{1}{3} \pi r^{2}h[/tex]
This problem gives us the diameter, which is twice of the radius. So, we'll just half it.
Radius (me) = 4 cm.
Substitute our given values into the equation.
[tex] \frac{1}{3} \pi (4)^{2}h \ or \ \frac{1}{3} \pi (4)^{2}(10) \ or \ \frac{1}{3} \pi (16)(10)[/tex]
Multiply
[tex] \frac{1}{3} \pi(160) \ or \ \frac{1}{3} (3.14)(160) \ or \ 1.047(160)[/tex]
Multiply
[tex]167.52 \ cm^{3}[/tex]
This would make [tex]167 \ cm^{3} [/tex] the closest option.
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