Discover answers to your most pressing questions at Westonci.ca, the ultimate Q&A platform that connects you with expert solutions. Get detailed and precise answers to your questions from a dedicated community of experts on our Q&A platform. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.
Sagot :
From the basic "heat lost by hot object=heat gained by colder object" principle, we have
m1c1ΔT1=m2c2ΔT2
where m1= 1kg
m2=4kg
c1=900J/kg k
c2=4200J/kg k
With this information at hand we have
m1c1(90-T)=m2c2(T-25)
after substituting the given values we can find that
T=28.3^{0}c
m1c1ΔT1=m2c2ΔT2
where m1= 1kg
m2=4kg
c1=900J/kg k
c2=4200J/kg k
With this information at hand we have
m1c1(90-T)=m2c2(T-25)
after substituting the given values we can find that
T=28.3^{0}c
By applying the Law of Conservation of Energy, the final temperature of water is equal to 28.63°C
Given the following data:
- Mass of aluminum metal = 1.00 kg
- Volume of water = 4 L
- Mass of water = 4.00 kg
- Temperature of aluminum metal = 90.0°C
- Initial temperature of water = 25.0°C
Scientific data:
- Specific heat capacity of water = 4200 J/kg°C
- Specific heat capacity of aluminum = 900 J/kg°C
Mathematically, quantity of heat energy is given by the formula;
[tex]Q=mc\theta[/tex]
Where:
- Q represents the quantity of heat energy.
- m represents the mass of an object.
- c represents the specific heat capacity.
- ∅ represents the change in temperature.
According to the Law of Conservation of Energy, we have:
The quantity of heat energy lost by the aluminum metal = The quantity of heat energy gained by the water.
[tex]Q_{lost} = Q_{gained}\\\\m_ac_a\theta_a = m_wc_w\theta_w\\\\1(900)(90 - T_f) = 4(4200)(T_f - 25)\\\\81000-900T_f =16800T_f - 420000\\\\16800T_f+900T_f=420000 + 81000\\\\T_f=\frac{501000}{17500} \\\\T_f=28.63[/tex]
Final temperature = 28.63°C
Read more: https://brainly.com/question/16735503
We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.
