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What is the approximate volume of a cone with a height of 11 ft and radius of 3 ft?
Use 3.14 to approximate pi, and round answers to two decimal places if necessary. Actually ttype in 3.14 don't use the symbol because it adds more numbers
___ft3
[tex] \pi [/tex] don't use this do 3.14

Sagot :

heyDB
Substitute the values of the radius (r=3), the height (h=11), and an approximation of Pi (3.14) into the formula to find the volume of the cone.
V≈+1/3⋅3.14⋅3^2⋅11

Simplify.
Write 3.14 as a fraction with denominator 1. 
V≈+1/3⋅3.14/1 

Combine 1/3 and 3.14/1 to get 3.14/3. 
V≈+3.14/3 

Replace back in to larger expression. 
V≈+3.14/3⋅3^2⋅11 

Divide 3.14 by 3 to get 1.04666667.
V≈+1.04666667⋅3^2⋅11

Raise 3 to the power of 2 to get 9.
V≈+1.04666667⋅9⋅11

Multiply 1.04666667 by 9 to get 9.42.
V≈+9.42⋅11

Multiply 9.42 by 11 to get 103.62.
V≈+103.62

Remove trailing zeros from 103.62.
V≈+103.62ft^3

Volume:
V≈+103.62ft^3
apologiabiology
so volue of a cone=1/3 times (area of base) times height
area of base=circle so

find area of base/circle

pi times r^2
3.14 times 3^2
3.14 times 9
28.26

1/3 times 28.26 times 11=103.62 cm^3
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