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the sum of two numbers is 36. twice the first number minus the second is 6. find the two numbers

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raymondtini2468
2x-y=6                            2x-y=6
x+y=36                           2(36-y)-y=6
                                      72-2y-y=6
x+y=36                           72-3y=6
 -y     -y                           -72   -72
x=36-y                           -3y=66
x=36-22                              -3y  -3y
x=14                                  y=22

The values of the two numbers are 14 and 22 respectively.

Let the numbers be represented by x and y

Based on the information given, the equation to represent the information will be:

x + y = 36 ..... i

2x - y = 6 ....... ii

Add equation i and ii together

3x = 42

x = 42/3

x = 14

Since x + y = 36

Then, we'll put the value of x into the equation and this will be:

x + y = 36

14 + y = 36

y = 36 - 14

y = 22

Therefore, the values of x and y are 14 and 22 respectively.

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