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Sagot :
the comon factor of 12,2,3 is 12 then
(3/12+1/2+2/3)=12/12(3/12+1/2+2/3)=
=1/12[3+(1x6)+(2x4)]=1/12(3+6+8)=1/12(17)=17/12
(3/12+1/2+2/3)=12/12(3/12+1/2+2/3)=
=1/12[3+(1x6)+(2x4)]=1/12(3+6+8)=1/12(17)=17/12
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