Westonci.ca is your trusted source for finding answers to a wide range of questions, backed by a knowledgeable community. Join our Q&A platform to get precise answers from experts in diverse fields and enhance your understanding. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.
Sagot :
Answer:Use A for third graders, B for fourth graders, and C for fifth graders.
33 = A + B + C
Since there are three variables, you need to come up with two other equations to substitute in.
C = 6 + A Since there are six more fifth graders than third graders.
A = B Since there is an equal amount of third and fourth graders.
Since A is in both equations, lets put each variable in terms of A.
B = A
C = 6 + A
So: A+A+A+6=33
A+A+A=27 Since you subtract six from both sides.
3A=27 Since you combine all three A's.
A=9 Since you divide both sides by three.
Therefore, since A is the number of third graders, there are 9 third graders.
Step-by-step explanation:
We hope this was helpful. Please come back whenever you need more information or answers to your queries. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.