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what is the zero for 2x2-7=4

Sagot :

apologiabiology
2x^2-7=4
subtract 4 from both sdies
2x^2-11=0
therefor
2x^2=11
divide by 2
x^2=5.5
square root both sdies
x=-2.345 or 2.345
Panoyin
2x² - 7 = 4
      +7  +7
      2x² = 11
        2      2
        x² = 5 1/2
         x = √5 1/2
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