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solve the following by using factoring.
x^2-3x=10


Sagot :

It must be x^2-3x+10 Then we can solve by factoring X^2-3x+10
x² - 3x = 10
x² - 3x - 10 = 0
(x - 5)(x + 2) = 0
x = -(-3) +/- √((-3)² - 4(1)(-10)
                     2(1)
x = 3 +/- √(9 + 40)
                 2
x = 3 +/- √49
             2
x = 3 +/- 7
           2
x = 3 + 7    x = 3 - 7
         2                2
x = 10        x = -4
       2                2
x = 5          x = -2