Welcome to Westonci.ca, your ultimate destination for finding answers to a wide range of questions from experts. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.

HELP PLEASE
If the radius of the base of the cone, r, is 2 feet and the height,h, is 12 feet, what is the volume of the cone?

HELP PLEASE If The Radius Of The Base Of The Cone R Is 2 Feet And The Heighth Is 12 Feet What Is The Volume Of The Cone class=

Sagot :

For a cone, the equation for volume would be
V = π r^2 h/3.

( volume = pi x radius squared x height / 3)

To find the volume for this question, you would set up the equation like this:

V = π x 2^2 x 12 / 3

Then, following the order of operation, you would do the following:

V = π x 4 x 12 / 3

(You get the 4 from 2 squared)

V = π x 4 x 4

(You get the second 4 from dividing 12 by 3)

V = π x 16

(You get 16 from multiplying 4 and 4)

V = 16π

(You get 16π from multiplying 16 and π, and the number is always in front of the π, so you would never get a π16, it would only be 16π)

So, your volume would be 16π, which is answer D.

I hope I helped! c: