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Sagot :
Because area's formula is length times width, 10 times 6 =60 giving you the answer.
Area of a hexagon with the side length 10...
Well this hexagon would be made up of 12 right angled triangles each with an area of:
[tex]\frac { 25 }{ 2 } \sqrt { 3 } { units }^{ 2 }[/tex]
So the area of this hexagon would be:
[tex]A=12\cdot \frac { 25 }{ 2 } \sqrt { 3 } { units }^{ 2 }\\ \\ =6\cdot 25\sqrt { 3 } { units }^{ 2 }\\ \\ =150\sqrt { 3 } { units }^{ 2 }[/tex]
Well this hexagon would be made up of 12 right angled triangles each with an area of:
[tex]\frac { 25 }{ 2 } \sqrt { 3 } { units }^{ 2 }[/tex]
So the area of this hexagon would be:
[tex]A=12\cdot \frac { 25 }{ 2 } \sqrt { 3 } { units }^{ 2 }\\ \\ =6\cdot 25\sqrt { 3 } { units }^{ 2 }\\ \\ =150\sqrt { 3 } { units }^{ 2 }[/tex]
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