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Sagot :
[tex]-\dfrac{ax}{b}\geq c-d\\
-ax\geq bc-bd\\
x\leq-\dfrac{bc-bd}{a}\\
x\leq\dfrac{bd-bc}{a}
[/tex]
We will see that the solution of the given inequality is:
[tex]\frac{ -(c - d)*b}{a} \ge x[/tex]
How to solve the inequality?
Here we have the inequality:
[tex]-\frac{ax}{b} \ge c - d[/tex]
To solve it, we need to isolate x on one side of the inequality.
First, we can multiply both sides for b:
[tex]-ax \ge (c - d)*b[/tex]
Now we divide both sides by -a, because we are operating with a negative number, we need to change the direction of the greater than or equal to sign, so we will get:
[tex]\frac{ -(c - d)*b}{a} \ge x[/tex]
That is the solution to the given inequality.
If you want to learn more about inequalities:
https://brainly.com/question/18881247
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