Answered

Discover the best answers at Westonci.ca, where experts share their insights and knowledge with you. Our platform offers a seamless experience for finding reliable answers from a network of experienced professionals. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

The prism has a surface area of 202 ft2.



What would the surface area of the prism be if each dimension were tripled?



ft2

Sagot :

arnfrs
Let's call the dimensions of the prism (I will assume it is rectangular) a, b, and c.

The surface area is:

[tex]2ab + 2ac + 2bc = 202[/tex]

The dimensions of the new prism are 3a, 3b, and 3c.

This surface area would be:

[tex]2(3a)(3b) + 2(3a)(3c) + 2(3b)(3c) = [/tex]

[tex]2(9ab) + 2(9ac) + 2(9bc) = [/tex]

[tex]9(2ab + 2ac + 2bc) = [/tex]

[tex]9(202) = \boxed{1818}[/tex]

Hope this helps :D


Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.