Answered

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Simplify please (x^2/9x^2-4y^2)/(x^2/2y-3x)

Sagot :

9x²-4y²=(3x-2y)*(3x+2y)

Solution: [tex] \frac{ x^{2} }{(3x-2y)*(3x+2y)} : \frac{x^2}{2y-3x} = \frac{ x^{2} }{(3x-2y)*(3x+2y)} * \frac{2y-3x}{x^2} \\ \\ =- \frac{1}{3x+2y} [/tex]
     x²      ÷    x²          x²        × 2y - 3x = -x + y
9x² - 4y²    2y - 3x     9x² - 4y²         x²        2x - 3y