Answered

Looking for answers? Westonci.ca is your go-to Q&A platform, offering quick, trustworthy responses from a community of experts. Join our platform to connect with experts ready to provide detailed answers to your questions in various areas. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.

what is the vertex for the equation f(x)=3(x+4)^2-5

Sagot :

Take derivative..
f'(x) = 3*2*(x+4)
f'(x) is must be equal to 0.
6*(x+4)=0
x=-4

for x=-4; what is the y value?
for x=-4; f(x)=-5

the vertex is (-4,-5)
Panoyin
f(x) = 3(x + 4)² - 5
f(x) = 3(x + 4)(x + 4) - 5
f(x) = 3(x² + 4x + 4x + 16) - 5
f(x) = 3(x² + 8x + 16) - 5
f(x) = 3(x²) + 3(8x) + 3(16) - 5
f(x) = 3x² + 24x + 48 - 5
f(x) = 3x² + 24x + 43
Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.