Answered

Discover the answers you need at Westonci.ca, where experts provide clear and concise information on various topics. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

What's the answer too x+7/7x+35*x^2-3x-40/x-8

Sagot :

[tex]\frac{x+7}{7x+35}\cdot\frac{x^2-3x-40}{x-8}=(*)\\\\x^2-3x-40=0\\a=1;\ b=-3;\ c=-40\\\Delta=b^2-4ac;\ x_1=\frac{-b-\sqrt\Delta}{2a};\ x_2=\frac{-b+\sqrt\Delta}{2a}\\\\\Delta=(-3)^2-4\cdot1\cdot(-40)=9+160=169;\ \sqrt\Delta=\sqrt{169}=13\\\\x_1=\frac{3-13}{2\cdot1}=\frac{-10}{2}=-5;\ x_2=\frac{3+13}{2\cdot1}=\frac{16}{2}=8\\\\x^2-3x-40=(x+5)(x-8)\\\\(*)=\frac{x+7}{7(x+5)}\cdot\frac{(x+5)(x-8)}{x-8}=\frac{x+7}{7}=\frac{x}{7}+\frac{7}{7}=\frac{1}{7}x+1\\\\D:x\neq-5\ \wedge\ x\neq8[/tex]
We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.