Westonci.ca is the Q&A platform that connects you with experts who provide accurate and detailed answers. Get immediate and reliable answers to your questions from a community of experienced experts on our platform. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.
Sagot :
Since both these cars are traveling as an assumed constant rate, you can imagine them as not moving at all to make the problem easier conceptually. The distance between the cars will also remain constant. First, convert the units km/hr into m/s: 90/3.6= 25 m/s; 50/3.6=13.89 m/s. The difference between these two speeds is 11.11 m/s. Now use the equation: velocity= distance/time. 11.11= 100/time; solve for time and you should get 9.0009 seconds
The faster car behind is catching up/closing the gap/gaining on
the slow truck in front at the rate of (90 - 50) = 40 km/hr.
At that rate, it takes (100 m) / (40,000 m/hr) = 1/400 of an hour
to reach the truck.
(1/400 hour) x (3,600 seconds/hour) = 3600/400 = 9 seconds, exactly
Thank you for your visit. We are dedicated to helping you find the information you need, whenever you need it. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.