Hugo10
Answered

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find the zeros of x^2+4x=-10 using the quadratic formula

Sagot :

x^2+4+10=0
x=(-4(+/-)root16-40)/2, so we now know that the zeros are imaginary, because you can't square root a negative number and 16-40 is -24
so the two roots are…
-2+iroot6 and -2-iroot6

Panoyin
x² + 4x = 10
x² + 4x - 10 = 10 - 10
x² + 4x - 10 = 0
x = -4 +/- √(4² - 4(1)(-10))
                   2(1)
x = -4 +/- √(16 + 40)
                 2
x = -4 +/ √56
             2
x = -4 +/- √(4 × 14)
               2
x = -4 +/- √4 √14
                2
x = -4 +/- 2√14
              2
x = -4 +/- 2(3.741657387)
                      2
x = -4 +/- 7.483314774
                    2
x = -4 + 7.483314774    x = -4 - 7.483314774
                   2                                    2
x = 3.483314774           x = -11.483314774
               2                                      2
x = 1.741657387           x = -5.741657387

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