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Sagot :
Because mechanical energy is conserved, potential energy due to gravity will equal the kinetic energy of the used to throw the ball. This is represented by mgh=.5mv^2
1. Divide both sides of the equation by m to ignore mass. The new equation will be gh=.5v^2
2. Substitute values into the equation: 9.8h=(.5)(10^2)--> 9.8h=50
3. Divide 50 by 9.8 to get h=5.102m
1. Divide both sides of the equation by m to ignore mass. The new equation will be gh=.5v^2
2. Substitute values into the equation: 9.8h=(.5)(10^2)--> 9.8h=50
3. Divide 50 by 9.8 to get h=5.102m
Explanation:
Given that
The weight of a ball, [tex]W=7\ N[/tex]
Initial velocity of the ball, [tex]v=10\ m/s[/tex]
The principle of conservation of mechanical energy states that, the total energy of a system remains conserved. The mathematical form of the principle of conservation of mechanical energy is :
[tex]\dfrac{1}{2}mv^2=mgh[/tex]
Where
m is the mass of the object
v is the velocity
h is the height
Using the conservation of energy,
[tex]\dfrac{1}{2}mv^2=mgh\\\\\dfrac{1}{2}v^2=gh[/tex]
Solving for h,
[tex]h=\dfrac{v^2}{2g}[/tex]
Put all the values,
[tex]h=\dfrac{(10)^2}{2\times 9.8}\\\\h=5.10\ m[/tex]
Answer:
The maximum height achieved by the ball is [tex]5.1\ m[/tex].
Reference:
brainly.com/question/20971995
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