bsktbll23jordan
Answered

Explore Westonci.ca, the premier Q&A site that helps you find precise answers to your questions, no matter the topic. Experience the convenience of finding accurate answers to your questions from knowledgeable professionals on our platform. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

You're conducting a physics experiment on another planet. You drop a rock from a height of 2.3 m and it hits the ground 1.1 seconds later. What is the acceleration due to gravity on this planet?
A. 4.2 m/s2
B. 3.8 m/s2
C. 2.4 m/s2
D. 9.8 m/s2

Sagot :

You get [tex]2.3=1.21*\frac{a}2[/tex] or [tex]4.6=1.21a[/tex] or [tex]a=3.802[/tex] (B)

Acceleration due to gravity on this planet will be 3.802 m / s^2

What are equations of motion?

Equation of motion are defined as equations that describe the behavior of a physical system in terms of its motion as a function of time

Using equation of motion

u=0

s= 2.3 m

t = 1.1 sec

to find = g (acceleration due to gravity on this planet)

s = u t + 1/2 (a ) (t ^(2))

s = 1/2 (g) (t^2)

2.3 = 1/2 (g) (1.1^2)

g = 2 * 2.3 /(1.1)^2

g = 4.6 /1.21= 3.802

correct answer is b) g = 3.802 m / s^2

Learn more about equation of motion

https://brainly.com/question/14927180?referrer=searchResults

#SPJ2

We appreciate your visit. Hopefully, the answers you found were beneficial. Don't hesitate to come back for more information. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.