Answered

Looking for reliable answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Get quick and reliable solutions to your questions from a community of seasoned experts on our user-friendly platform. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.

you throw a rock straight up into the air with a speed of 11.5 m/s. How long does it take the rock to reach its highest point?

Sagot :

acceleration=a=-9.8 m/s^2
Initial velocity= 11/5 m/s
Final velocity is 0 at the rock's highest point
Use the equation Final Velocity= Initial Velocity + Acceleration x Time
Substitute values: 0= 11.5+-9.8t
t= -11.5/-9.8
t= 1.1735s
AL2006

The acceleration of gravity is  9.8m/s²  downward.

That means that if no other vertical forces but gravity act on an object,
then the object's downward speed increases by  9.8m/s  every second,
or its upward speed decreases by the same amount every second.

So if a rock starts out moving in the upward direction at 11.5 m/s, and the
only vertical force on it is the force of gravity, then it will lose 9.8 more m/s
of upward speed every second, and will totally run out of upward gas after 

             11.5 / 9.8 = 1.173 seconds .


Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.