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A cone-shaped container sits inside a larger cone. The inner cone has a height of 3 in. and a diameter of 5 in. The outer cone has the same diameter and is 14 in. tall. The extra space in the outer cone is filled with crushed ice to keep the contents of the inner cone cool.

What is the volume of crushed ice? Round your answer to two decimal places and use 3.14 to approximate pi.


Sagot :

volume of cone=1/3 time (area of base=circle) times height

iner cone=1/3 times pi times radius^2 times 3
diameter/2=radius
5/2=2.5
1/3 times 3.14 times 2.5^2 times 3=19.625=volume of inner cone


outer cone=14 times 3.14 times 2.5^2 times 1/3=91.5833
subtract
91.5833-19.625=71.9583
round
71.96 in^3