gtafolla1203
Answered

Get the answers you need at Westonci.ca, where our expert community is always ready to help with accurate information. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

How do I solve 28=64-9x^2 using square roots?

Sagot :

1. Subtract 64 from each side of the equation

-36=-9x^2

2. Separate -9 from x^2 by dividing -9 from each side. The negatives will cancel leaving a positive on the left.

4=x^2

3. Last, take the square root of each side in order to get rid of the exponent.

2=x

4. Quick Check

28=64-9(2)^2
28=64-9(4)
28=64-36
28=28
[tex]28=64-9{ x }^{ 2 }\\ \\ 9{ x }^{ 2 }=64-28\\ \\ 9{ x }^{ 2 }=36[/tex]

[tex]\\ \\ \frac { 1 }{ 9 } \cdot 9{ x }^{ 2 }=\frac { 1 }{ 9 } \cdot 36\\ \\ { x }^{ 2 }=4\\ \\ x=\pm \sqrt { 4 }[/tex]

[tex]\\ \\ \therefore \quad x=\pm 2[/tex]
We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.