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A current of 3.60A flows for 15.3s through a conductor. Calculate the number of electrons that pass through a point in the conductor in this time

Sagot :

AL2006

3.60 A = 3.60 coulombs of charge per second

(3.60 Coul/sec) x (15.3 sec) = 55.08 coulombs of charge

1 coulomb of charge is carried by 6.25 x 10^18 electrons

Number of electrons =

               (55.08 Coul) x (6.25 x 10^18 e/coul) = 3.4425 x 10^20 electrons

Answer: 3.44 x 10^20

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