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Sagot :
1. Let n = Tom's weight in pounds.
m=Jim's weight in pounds.
m=n - 30
m+n=210
We solve this by substitution:
(n - 30)+n=210
2n-30=210
2n=210+30
2n=240
n=120 pounds weighs Tom
m=120-30=90 pounds weighs Jim
2. Let n = the number of boys.
g = the number of girls.
n+g=19
g=n+5
By substitution:
n+(n+5)=19
2n+5=19
2n=19-5
2n=14
n=14:2
n=7 boys
g=7+5=12 girls
3. Let n = the shortest side of the triangle
each of the two sides that are equal in length=2n
The perimeter=n+2n+2n=36 inches
5n=36
n=7.2 inches is the shortest side of the triangle
2*7.2=14.4 inches is each of the two sides that are equal in length
m=Jim's weight in pounds.
m=n - 30
m+n=210
We solve this by substitution:
(n - 30)+n=210
2n-30=210
2n=210+30
2n=240
n=120 pounds weighs Tom
m=120-30=90 pounds weighs Jim
2. Let n = the number of boys.
g = the number of girls.
n+g=19
g=n+5
By substitution:
n+(n+5)=19
2n+5=19
2n=19-5
2n=14
n=14:2
n=7 boys
g=7+5=12 girls
3. Let n = the shortest side of the triangle
each of the two sides that are equal in length=2n
The perimeter=n+2n+2n=36 inches
5n=36
n=7.2 inches is the shortest side of the triangle
2*7.2=14.4 inches is each of the two sides that are equal in length
Answer: . Let n = Tom's weight in pounds.
m=Jim's weight in pounds.
m=n - 30
m+n=210
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