Answered

At Westonci.ca, we connect you with the best answers from a community of experienced and knowledgeable individuals. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.

A car leaves a town traveling at 60 miles per hour. Two hours later, a second car leaves the town traveling the same route and overtakes the first car in 6 hours and 40 minutes. How fast was the second car traveling?

Sagot :

AL2006

After two hours, the first car has traveled (2 x 60) = 120 miles.
That's the gap that the second car has to close.

The second car closes the gap of 120 miles in 6-2/3 hours.
He must have exceeded the first car's speed by (120/6-2/3) mph.

6-2/3 = 20/3

120 divided by 20/3  =  120 x 3/20 = 360/20  =  18 mph

The second car exceeded the first car's speed by 18 mph,
so he had to be traveling (60 + 18) = 78 mph to catch up.

Check:

In 6-2/3 hours . . .

The first car covers  (60 x 20/3) = 400 miles.

The second car covers  (78 x 20/3) = 520 miles.
This is the same distance as the first car PLUS the 120
that he was behind when he started out.
                                                                     yay !
78 mph
The second car travels 520 miles in 400 minutes. 520/400=1.3. 1.3*60=78.
Thanks for stopping by. We are committed to providing the best answers for all your questions. See you again soon. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.