Answered

Westonci.ca is your go-to source for answers, with a community ready to provide accurate and timely information. Connect with professionals ready to provide precise answers to your questions on our comprehensive Q&A platform. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.

how do i solve 1-6Log(6x-7)=13 ????

Sagot :

konrad509
[tex]D:6x-7>0\\ D:6x>7\\ D:x>\dfrac{7}{6}\\\\ 1-6\log(6x-7)=13 \\ 6\log(6x-7)=-12\\ \log(6x-7)=-2\\ 10^{-2}=6x-7\\ 6x-7=\dfrac{1}{100}\\ 600x-700=1\\ 600x=701\\ x=\dfrac{701}{600} [/tex]
[tex]1-6\log { \left( 6x-7 \right) } =13\\ \\ -6\log { \left( 6x-7 \right) } =12[/tex]

[tex]\\ \\ \frac { -6\log { \left( 6x-7 \right) } }{ -6 } =\frac { 12 }{ -6 } \\ \\ \log { \left( 6x-7 \right) } =-2[/tex]

[tex]\\ \\ { 10 }^{ -2 }=6x-7\\ \\ 6x-7=\frac { 1 }{ 100 } \\ \\ 6x=7+\frac { 1 }{ 100 }[/tex]

[tex]\\ \\ 6x=\frac { 700 }{ 100 } +\frac { 1 }{ 100 } \\ \\ 6x=\frac { 701 }{ 100 } [/tex]

[tex]\\ \\ \frac { 1 }{ 6 } \cdot 6x=\frac { 1 }{ 6 } \cdot \frac { 701 }{ 100 } \\ \\ x=\frac { 701 }{ 600 } [/tex]
Thanks for stopping by. We are committed to providing the best answers for all your questions. See you again soon. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.