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how do i solve 1-6Log(6x-7)=13 ????

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konrad509
[tex]D:6x-7>0\\ D:6x>7\\ D:x>\dfrac{7}{6}\\\\ 1-6\log(6x-7)=13 \\ 6\log(6x-7)=-12\\ \log(6x-7)=-2\\ 10^{-2}=6x-7\\ 6x-7=\dfrac{1}{100}\\ 600x-700=1\\ 600x=701\\ x=\dfrac{701}{600} [/tex]
[tex]1-6\log { \left( 6x-7 \right) } =13\\ \\ -6\log { \left( 6x-7 \right) } =12[/tex]

[tex]\\ \\ \frac { -6\log { \left( 6x-7 \right) } }{ -6 } =\frac { 12 }{ -6 } \\ \\ \log { \left( 6x-7 \right) } =-2[/tex]

[tex]\\ \\ { 10 }^{ -2 }=6x-7\\ \\ 6x-7=\frac { 1 }{ 100 } \\ \\ 6x=7+\frac { 1 }{ 100 }[/tex]

[tex]\\ \\ 6x=\frac { 700 }{ 100 } +\frac { 1 }{ 100 } \\ \\ 6x=\frac { 701 }{ 100 } [/tex]

[tex]\\ \\ \frac { 1 }{ 6 } \cdot 6x=\frac { 1 }{ 6 } \cdot \frac { 701 }{ 100 } \\ \\ x=\frac { 701 }{ 600 } [/tex]
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