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Titik A (10,P) ,terletak pada garis yang melalui tiitik B (3,1) dan C (-4,-13) . nilai P adalah ?

Sagot :

Lilith
[tex] B (3,1), \ \ \ C (-4,-13) \\ \\ First \ find \ the \ slope \ of \ the \ line \ thru \ the \ points \: \\ \\ m= \frac{y_{2}-y_{1}}{x_{2}-x_{1} } \\ \\m=\frac{ -13-1}{-4-3} = \frac{-14}{-7}=2 \\ \\ Use \ point \ form \ of \ a \ line\ with \ one \ point: \\ \\ y-y_{1} =m(x-x _{1})\\\\ y-1 =2(x-3)\\\\y =2 x-6 +1\\\\y =2 x-5[/tex]

[tex]Titik \ \ A (10,P) \\\\P=2*10-5\\\\P=20-5\\\\P=15\\\\Answer:\ \ Titik \ \ A (10,P)=(10,15)[/tex]


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