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If 5 times a number is increased by 4, the result is at least 19. Find the least possible number that satisfies these conditions?

Sagot :

First let's call this number x, 5 times the number is 5x and if we increase it by 4 it will be 5x+4 . Now, if 5x+4 is at least equal to 19, it means, it can only be equal to 19 and be greater than 19. So if we show this as an inequality :

[tex]5x+4\ge 19[/tex]

The least value this expression can have is 19, so let's take 19 as the value and solve.


[tex]5x+4=19\\ 5x=19-4\\ 5x=15\\ \\ x=\frac { 15 }{ 5 } \\ \\ x=3[/tex]

So the least possible number that satisfies these conditions is 3.
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