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Sagot :
[tex]De finition:\\\sqrt{a}=b\ \iff b^2=a\\=====================\\\\[/tex]
[tex]625|5\\125|5\\.\ 25|5\\.\ \ 5|5\\.\ \ 1|\\\\625=5\times5\times5\times5=5^2\times5^2\\\\\sqrt{625}=\sqrt{5^2\times5^2}=(*)\\-------------------------------\\use:\ \sqrt{a\times b}=\sqrt{a}\times\sqrt{b}\ and\ \sqrt{a^2}=a\ for\ a\geq0\\-------------------------------\\(*)=\sqrt{5^2}\times\sqrt{5^2}=5\times5=\boxed{25}[/tex]
[tex]Other\ solution:\\\\\sqrt{625}=25\ because\ 25^2=25\times25=625[/tex]
[tex]625|5\\125|5\\.\ 25|5\\.\ \ 5|5\\.\ \ 1|\\\\625=5\times5\times5\times5=5^2\times5^2\\\\\sqrt{625}=\sqrt{5^2\times5^2}=(*)\\-------------------------------\\use:\ \sqrt{a\times b}=\sqrt{a}\times\sqrt{b}\ and\ \sqrt{a^2}=a\ for\ a\geq0\\-------------------------------\\(*)=\sqrt{5^2}\times\sqrt{5^2}=5\times5=\boxed{25}[/tex]
[tex]Other\ solution:\\\\\sqrt{625}=25\ because\ 25^2=25\times25=625[/tex]
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