Answered

Get reliable answers to your questions at Westonci.ca, where our knowledgeable community is always ready to help. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

3p^2-2p-5 factor completely

Sagot :

LoganTutor99
[tex]a x^{2} +bx+c[/tex] Here is the basis equation. [tex]3p ^{2} -2p-5[/tex] Let us use the AC method. Multiple the A and C values, or 3 and -5. This is -15. So now ask yourself... what multiplies to -15 but adds to -2. that would be, -5 and 3. So now reconstruct your equation ...[tex](3p^2+3p)+(-5p-5)[/tex] The larger number will go first (3>-5) Now you can factor each group. [tex]3p(p+1)-5(p+1)[/tex] Because what is now in the parentheses are qualm and they are being added, you can now make the coeffecients a group [tex](3p-5) (p+1)[/tex] If you are solving for p, set equal to zero and then the answers are -1 and (5/3). If you are just factoring, then that is your answer.
3p^2-2p-5
(3p-5) (p+1)

analyzing
-5 tells me the signs are different, therefore use subtraction
5 and 1 are the only possible combinations for 5
the same for 3
trial and error
We appreciate your time. Please come back anytime for the latest information and answers to your questions. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.