Answered

Welcome to Westonci.ca, where your questions are met with accurate answers from a community of experts and enthusiasts. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.

how to solve 3 log8⁡〖X〗 +2logX〖8〗 = 7 

Sagot :

konrad509
[tex]D:x>0 \wedge x\not=1\\ D:x\in(0,1)\cup(1,\infty)\\\\ 3\log_8x+2\log_x8=7\\ 3\log_8x+2\cdot\dfrac{1}{\log_8x}=7\\ 3\log_8^2x+2=7\log_8x\\ 3\log_8^2x-7\log_8x+2=0\\ 3\log_8^2x-6\log_8x-\log_8x+2=0\\ 3\log_8x(\log_8x-2)-1(\log_8x-2)=0\\ (3\log_8x-1)(\log_8x-2)=0\\ 3\log_8x-1=0 \vee \log_8x-2=0\\ \log_8x^3=1 \vee \log_8x=2\\ x^3=8 \vee x=8^2\\ x=2 \vee x=64\\ [/tex]
We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.