Answered

At Westonci.ca, we provide reliable answers to your questions from a community of experts. Start exploring today! Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.

how to solve 3 log8⁡〖X〗 +2logX〖8〗 = 7 

Sagot :

konrad509
[tex]D:x>0 \wedge x\not=1\\ D:x\in(0,1)\cup(1,\infty)\\\\ 3\log_8x+2\log_x8=7\\ 3\log_8x+2\cdot\dfrac{1}{\log_8x}=7\\ 3\log_8^2x+2=7\log_8x\\ 3\log_8^2x-7\log_8x+2=0\\ 3\log_8^2x-6\log_8x-\log_8x+2=0\\ 3\log_8x(\log_8x-2)-1(\log_8x-2)=0\\ (3\log_8x-1)(\log_8x-2)=0\\ 3\log_8x-1=0 \vee \log_8x-2=0\\ \log_8x^3=1 \vee \log_8x=2\\ x^3=8 \vee x=8^2\\ x=2 \vee x=64\\ [/tex]
We appreciate your time. Please revisit us for more reliable answers to any questions you may have. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.