At Westonci.ca, we connect you with experts who provide detailed answers to your most pressing questions. Start exploring now! Get immediate and reliable answers to your questions from a community of experienced experts on our platform. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.
Sagot :
1. 3rd one, because for each x there's only one y.
2. The domain are x's, so it's {2, 4, 6, 8}
3. The range are y's, so it's {1, 2, 3, 4}
4.
[tex]p=kd\\ 7=3k\\ k=\dfrac{7}{3}\\ p=\dfrac{7}{3}d\\ d=\dfrac{3}{7}p\\ d=\dfrac{3}{7}\cdot28=12[/tex]
5. [tex]T(-4)=7-(-4)=7+4=11[/tex]
6. [tex]f(x) = - |x| + 2[/tex]
7.
[tex]C=kt\\ 800=4k\\ k=200\\ C=200t[/tex]
2. The domain are x's, so it's {2, 4, 6, 8}
3. The range are y's, so it's {1, 2, 3, 4}
4.
[tex]p=kd\\ 7=3k\\ k=\dfrac{7}{3}\\ p=\dfrac{7}{3}d\\ d=\dfrac{3}{7}p\\ d=\dfrac{3}{7}\cdot28=12[/tex]
5. [tex]T(-4)=7-(-4)=7+4=11[/tex]
6. [tex]f(x) = - |x| + 2[/tex]
7.
[tex]C=kt\\ 800=4k\\ k=200\\ C=200t[/tex]
[tex]1.\\\#1\ not\ because\ for\ x=-2\to y=2\ and\ y=6\\\#2\ not\ because\ for\ x=1\to y=1\ and\ y=2\\\#3\ \boxed{IT'S\ OK}\leftarrow answer\\\#4\ not\ because\ for\ x=1\to y=2\ and\ y=3\ and...[/tex]
[tex]2.\ (x;\ y)\to x\in D-domain\\\\therefore:\\\\\{(2;1);\ (4;2);\ (6;\ 3);\ (8;\ 4)\}\\\\\boxed{The\ domain\ D=\{2;\ 4;\ 6;\ 8\}}[/tex]
[tex]3.\ (x;\ y)\to y\in Range\\\\\{(2;\ 1);\ (4;\ 2);\ (6;\ 3);\ (8;\ 4)\}\\\\\boxed{the\ range:\{1;\ 2;\ 3;\ 4\}}[/tex]
[tex]4.\\\frac{p}{d}=constans\\\\\frac{28}{d}=\frac{7}{3}\ \ \ \ |cross\ multiply\\\\7\cdot d=3\cdot28\ \ \ \ |divide\ both\ sides\ by\ 7\\\\d=\frac{84}{7}\\\\\boxed{d=12}[/tex]
[tex]5.\ T(z)=7-z\\\\T(-4)\to z=-4\\\\put\ the\ value\ of\ z\ to\ (7-z):\\\\T(-4)=7-(-4)=7+4=\boxed{11}[/tex]
[tex]6.\\y=|x|\to\ the\ axis\ of\ symmetry\ is\ OY\ (S_{OY})\\\\y=-|x|\to\ the\ axis\ of\ symmetry\ is\ OX\ (S_{OX})\\\\so....\ the\ y-intercept\ is\ (0;\ 2),\ therefore\ answer\ is\ \boxed{f(x)=-|x|+2}[/tex]
[tex]7.\\\begin{array}{ccc}C&-&t\\800&-&4\end{array}\ \ \ \ |cross\ multiply\\\\4C=800t\ \ \ \ \ |divide\ both\ sides\ by\ 4\\\\\boxed{C=200t}[/tex]
[tex]2.\ (x;\ y)\to x\in D-domain\\\\therefore:\\\\\{(2;1);\ (4;2);\ (6;\ 3);\ (8;\ 4)\}\\\\\boxed{The\ domain\ D=\{2;\ 4;\ 6;\ 8\}}[/tex]
[tex]3.\ (x;\ y)\to y\in Range\\\\\{(2;\ 1);\ (4;\ 2);\ (6;\ 3);\ (8;\ 4)\}\\\\\boxed{the\ range:\{1;\ 2;\ 3;\ 4\}}[/tex]
[tex]4.\\\frac{p}{d}=constans\\\\\frac{28}{d}=\frac{7}{3}\ \ \ \ |cross\ multiply\\\\7\cdot d=3\cdot28\ \ \ \ |divide\ both\ sides\ by\ 7\\\\d=\frac{84}{7}\\\\\boxed{d=12}[/tex]
[tex]5.\ T(z)=7-z\\\\T(-4)\to z=-4\\\\put\ the\ value\ of\ z\ to\ (7-z):\\\\T(-4)=7-(-4)=7+4=\boxed{11}[/tex]
[tex]6.\\y=|x|\to\ the\ axis\ of\ symmetry\ is\ OY\ (S_{OY})\\\\y=-|x|\to\ the\ axis\ of\ symmetry\ is\ OX\ (S_{OX})\\\\so....\ the\ y-intercept\ is\ (0;\ 2),\ therefore\ answer\ is\ \boxed{f(x)=-|x|+2}[/tex]
[tex]7.\\\begin{array}{ccc}C&-&t\\800&-&4\end{array}\ \ \ \ |cross\ multiply\\\\4C=800t\ \ \ \ \ |divide\ both\ sides\ by\ 4\\\\\boxed{C=200t}[/tex]
We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.