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How do u solve this:
Square root of 6x-9 equals x

Sagot :

anijlin
[tex] \sqrt{6x-9} = x[/tex]

first we are going to get rid of the square root by raising both sides to the power of 2

6x - 9 = x²
x² - 6x + 9 = 0

now the equation is a quadratic, and you can solve for x 

i'm going to factor it, but there are many ways to solve for a quadratic
(x - 3)(x - 3) = 0
If you FOIL this, it becomes x² - 6x + 9 

(x - 3)² = 0
x - 3 = 0
x = 3

to check the answer, you can plug 3 back into the original equation

[tex] \sqrt{6(3) - 9} = 3 [/tex]
[tex] \sqrt{18 - 9} = 3[/tex]
[tex] \sqrt{9} = 3[/tex]
[tex]3 = 3[/tex]
√6x-9=x
6x-9=x²
x²-6x+9=0
(x-3)(x-3)=0
x=3
check
√6*3-9=3
√18-9=3
√9=3
3=3
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