Answered

Explore Westonci.ca, the premier Q&A site that helps you find precise answers to your questions, no matter the topic. Our platform provides a seamless experience for finding precise answers from a network of experienced professionals. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.

The length of a rectangle is 4 more than twice the width the perimeter is 28 what is the length

Sagot :

anijlin
perimeter = length + length + width + width
if the perimeter is 28, then:
28 = length + length + width + width

if you know that the length is 4 more than twice the width, then:
length = 4 + 2 x width
(using L as length, and w as width then: L = 4 + 2w)

if you substitute that back into the equation
28 = L + L + w + w
you should get

28 = 4 + 2w + 4 + 2w + w + w
combine the 4's and the ws 
28 = 8 + 6w
subtract both sides by 8
22 = 6w
divide both sides by 6
w = 3 2/3

apologiabiology
perimiter=2(legnt+width)
or
p=2(l+w)

l=4+2w
p=28
28=2(l+w)
subsitte 4+2w for l
28=2(4+2w+w)
28=2(4+3w)
28=8+6w
subtract 8 from both sdies
20=6w
divide by 6
20/6=w
aprox
3 2/3=3.666666
so 3 2/3=width
Thank you for trusting us with your questions. We're here to help you find accurate answers quickly and efficiently. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Get the answers you need at Westonci.ca. Stay informed by returning for our latest expert advice.