TaishaDardy
Answered

Discover the answers to your questions at Westonci.ca, where experts share their knowledge and insights with you. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

the area of a playground is 20 square yards. The length of the playground is 5 times longer than its width. Find the length and width of the playground

Sagot :

anijlin
the area of a rectangle = length x width so:
A = l x w

if we know the area of the playground is 20 sq yards, then:

20 = l x w

if the length is 5 times the width, then:
l = 5w

We can combine these equations by substituting this " l " into the first equation:

20 = 5w x w

Now solve!

20 = 5w x w
combine the w's
20 = 5w²
divide both sides by 5
4 = w²
square root both sides
2 = w

The width of the playground is 2 yards. 

To find the length of the playground, you can plug that back into the equation
l = 5w 
l = 5(2)
l = 10

The length of the playground is 10 yards.








Thank you for choosing our service. We're dedicated to providing the best answers for all your questions. Visit us again. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.