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Sagot :
the area of a rectangle = length x width so:
A = l x w
if we know the area of the playground is 20 sq yards, then:
20 = l x w
if the length is 5 times the width, then:
l = 5w
We can combine these equations by substituting this " l " into the first equation:
20 = 5w x w
Now solve!
20 = 5w x w
combine the w's
20 = 5w²
divide both sides by 5
4 = w²
square root both sides
2 = w
The width of the playground is 2 yards.
To find the length of the playground, you can plug that back into the equation
l = 5w
l = 5(2)
l = 10
The length of the playground is 10 yards.
A = l x w
if we know the area of the playground is 20 sq yards, then:
20 = l x w
if the length is 5 times the width, then:
l = 5w
We can combine these equations by substituting this " l " into the first equation:
20 = 5w x w
Now solve!
20 = 5w x w
combine the w's
20 = 5w²
divide both sides by 5
4 = w²
square root both sides
2 = w
The width of the playground is 2 yards.
To find the length of the playground, you can plug that back into the equation
l = 5w
l = 5(2)
l = 10
The length of the playground is 10 yards.
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