A particle is moving along the curve y= 5 \sqrt{4 x + 1}. As the particle passes through the point (2, 15), its x-coordinate increases at a rate of 2 units per second. Find the rate of change of the distance from the particle to the origin at this instant.

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09-03-2015
Mathematics

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A particle is moving along the curve y= 5 \sqrt{4 x + 1}. As the particle passes through the point (2, 15), its x-coordinate increases at a rate of 2 units per second. Find the rate of change of the distance from the particle to the origin at this instant.

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Panoyin Panoyin · Answer 1 · 2015-03-09T20:55:15-04:00

Panoyin Panoyin

09-03-2015

[tex]y = 5 \sqrt{4x + 1} [/tex]

[tex]y = 5(2 x^{ \frac{1}{2} } + 1)[/tex]

[tex]y = 5(2 x^{ \frac{1}{2} }) + 5(1)[/tex]

[tex]y = 10 x^{ \frac{1}{2} } + 5[/tex]

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