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Eva wants to make two pieces of pottery. She needs 3/5 pound of clay for one piece and 7/10 pound of clay for the other piece. She has 3 bags of clay that weigh 4/5 pounds each. How many bags of clay will Eva need to make both pieces of pottery? How many pounds of clay will she have left?

Sagot :

calculista

we know that

Eva needs [tex] \frac{3}{5} [/tex] pound of clay for one piece and [tex] \frac{7}{10} [/tex] pound of clay for the other piece

Step 1

Find the total pound of clay for the two pieces

[tex] \frac{3}{5} +\frac{7}{10} =\frac{(2*3+7)}{10} \\ \\ =\frac{13}{10} pounds [/tex]

Eva has [tex] 3 [/tex] bags of clay that weigh [tex] \frac{4}{5} [/tex] pounds each.

Step 2

Find the total weigh of the [tex] 3 [/tex] bags of clay

[tex] 3*\frac{4}{5} =\frac{12}{5} pounds [/tex]

Part a ) How many bags of clay will Eva need to make both pieces of pottery?

by using proportion

[tex] \frac{1}{\frac{4}{5}} =\frac{x}{\frac{13}{10}} \\ \\ \frac{13}{10} =\frac{4}{5} x\\ \\ x=\frac{5*13}{4*10} \\ \\ x=\frac{65}{40} \\ \\ x=1.625bags [/tex]

therefore

the answer Part a)

she needs [tex] 2 [/tex] bags

Part b) How many pounds of clay will she have left?

Calculate the total weigh of the [tex] 3 [/tex] bags of clay minus the total pound of clay for the two pieces

so

[tex] \frac{12}{5} -\frac{13}{10} =\frac{(2*12-13)}{10} \\ \\ =\frac{(24-13)}{10} \\ \\ =\frac{11}{10} \\ \\ =1\frac{1}{10} pounds [/tex]

therefore

the answer Part b) is

[tex] 1\frac{1}{10} pounds [/tex]

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