Find the best solutions to your questions at Westonci.ca, the premier Q&A platform with a community of knowledgeable experts. Ask your questions and receive detailed answers from professionals with extensive experience in various fields. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.
Sagot :
The way i do it is factor x^2-12x+32 into (x-8)(x-4) then set each of those to zero which would look like 0=x-8 and 0=x-4. Then solve each equation and your answers would be x=8 and x=4
Answer:
The zeros are x=4, 8
Step-by-step explanation:
We have been given the function y=x^2-12x+32.
Let us write this in intercept form by factoring the given function.
We can factor it by AC method.
We can write the middle term -12x = -8x-4x
[tex]y=x^2-12x+32\\y=x^2-8x-4x+32\\\text{Now we take GCF}\\\\y=x(x-8)-4(x-8)\\\\y=(x-8)(x-4)[/tex]
Now, in order to find the zeros, we have
[tex](x-8)(x-4)=0\\\\x=4,8[/tex]
Therefore, the zeros are x=4, 8
We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.
