Explore Westonci.ca, the top Q&A platform where your questions are answered by professionals and enthusiasts alike. Explore thousands of questions and answers from knowledgeable experts in various fields on our Q&A platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.
Sagot :
The way i do it is factor x^2-12x+32 into (x-8)(x-4) then set each of those to zero which would look like 0=x-8 and 0=x-4. Then solve each equation and your answers would be x=8 and x=4
Answer:
The zeros are x=4, 8
Step-by-step explanation:
We have been given the function y=x^2-12x+32.
Let us write this in intercept form by factoring the given function.
We can factor it by AC method.
We can write the middle term -12x = -8x-4x
[tex]y=x^2-12x+32\\y=x^2-8x-4x+32\\\text{Now we take GCF}\\\\y=x(x-8)-4(x-8)\\\\y=(x-8)(x-4)[/tex]
Now, in order to find the zeros, we have
[tex](x-8)(x-4)=0\\\\x=4,8[/tex]
Therefore, the zeros are x=4, 8
We hope our answers were helpful. Return anytime for more information and answers to any other questions you may have. We hope this was helpful. Please come back whenever you need more information or answers to your queries. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.
