kylevanhart
Answered

Westonci.ca is your go-to source for answers, with a community ready to provide accurate and timely information. Discover comprehensive answers to your questions from knowledgeable professionals on our user-friendly platform. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

Calculate the power in kilowatts required to lift a 500 kg mass 12 meters in one second

Sagot :

AL2006

The weight of the load is (mass) x (gravity).

The work done to lift it is (weight) x (distance) = (mass) x (gravity) x (distance)

The power is (work)/(time) =

               (mass) x (gravity) x (distance) / (time)  = 

               (500 kg) x (9.8 m/s²) x (12 m) / (1 sec) =

                (500 x 9.8 x 12 / 1) (kg-m / sec²) (m) / (sec) =

                 (500 x 9.8 x 12 / 1)    newton  -  meter / sec =

                  (500 x 9.8 x 12 / 1)             joule        /  sec =

                                 58,800    watts

                         =       58.8 kW

                         =      about  78.8 horsepower
    

We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.