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how can you tell if 78 is divisible by 2,3or6

Sagot :

Well, first thing is 78 is an even number so 2 would automatically go into 78. For 3 & 6, you could skip count up to 78, or use a calculator if you really wanted to. Another thing you could do is look at what 3 & 6 go into. 12 x 6 = 72, and 72 + 6 = 78. For 3, 12 x 3 = 36, 36 x 2 = 72, 72 + 3 + 3 = 78. I hope this was helpful!
arnfrs
Use the divisibility rules (this applies to all integers)

For 2: a number is divisible by 2 if it ends in an even integer (10, 22, 34, 46, 58 all work)

For 3: a number is divisible by 3 if the sum of its integers is divisible by 3 (for instance, 15, 33, 27, etc.). To prove this we need to use modular arithmetic, which is a more advanced concept (high school), so just remember it for now

For 6: a number is divisible by 6 if it's divisible by both 2 and 3
For 78, 8 is an even number, so it is divisible by 2.

7 + 8 = 15, so it is divisible by 3

And because it is divisible by 2 and 3, it is also divisible by 6.

Alternatively, you could just quickly divide it by 2, 3, or 6 to see if there is a remainder

Hope this helps :D