At Westonci.ca, we connect you with experts who provide detailed answers to your most pressing questions. Start exploring now! Discover in-depth answers to your questions from a wide network of experts on our user-friendly Q&A platform. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.
Sagot :
[tex]ba^4\cdot(2ba^4)^{-3}=\dfrac{ba^4}{(2ba^4)^3}=\dfrac{ba^4}{8b^3a^{12}}=\dfrac{1}{8b^2a^8}[/tex]
[tex]a^{4}b(2ab^{4})^{-3} [/tex]
[tex]a^{4}b( \frac{1}{(2a^{4}b)^{3}})[/tex]
[tex]a^{4}b( \frac{1}{(2a^{4}b)(2a^{4}b)(2a^{4}b)}) [/tex]
[tex]a^{4}b( \frac{1}{8a^{12}b^{3}}) [/tex]
[tex] \frac{1}{8a^{8}b^{2}} [/tex]
[tex]a^{4}b( \frac{1}{(2a^{4}b)^{3}})[/tex]
[tex]a^{4}b( \frac{1}{(2a^{4}b)(2a^{4}b)(2a^{4}b)}) [/tex]
[tex]a^{4}b( \frac{1}{8a^{12}b^{3}}) [/tex]
[tex] \frac{1}{8a^{8}b^{2}} [/tex]
Thank you for trusting us with your questions. We're here to help you find accurate answers quickly and efficiently. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.