Welcome to Westonci.ca, your go-to destination for finding answers to all your questions. Join our expert community today! Connect with professionals on our platform to receive accurate answers to your questions quickly and efficiently. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.
Sagot :
so 9x^2+12x+4=0
so the quadratic formulat is (-b+/-(squrt(b^2-4ac)))/(2a)=x
subsitute
ax^2+bx+c=
9=a
12=b
4=c
(-12+/-(squrt(12^2-4(9)(4))))/(2(9))=x
(-12+/-(squrt(144^2-144)))/18)=x
(-12+/-0)/18)=x
-12/18=x
-2/3=x
so the quadratic formulat is (-b+/-(squrt(b^2-4ac)))/(2a)=x
subsitute
ax^2+bx+c=
9=a
12=b
4=c
(-12+/-(squrt(12^2-4(9)(4))))/(2(9))=x
(-12+/-(squrt(144^2-144)))/18)=x
(-12+/-0)/18)=x
-12/18=x
-2/3=x
[tex] Discriminant= b^{2}-4.a.c \\ \\ We\:need\:to:-b+ \sqrt{discriminant} /2a \\ \\ 9x^{2} +12x+4=0 \\ => 12^{2} -4.9.4 \\ 144-144=0 \\ \sqrt{0} =0 \\ \\ -12+ 0/18= \frac{-12}{18} = \frac{-2}{3} \\ \\ That`s\: enough=>x= \frac{-2}{3} \\ \\ \framebox[1.1\width]{Good Luck!} \par[/tex]
Thank you for choosing our service. We're dedicated to providing the best answers for all your questions. Visit us again. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.