Answered

Westonci.ca is the ultimate Q&A platform, offering detailed and reliable answers from a knowledgeable community. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

the perimeter of a rectangle is 66 cm and its width is half its length. what are the length and the width of the rectangle?

Sagot :

iGreen
P = 2(l + w)

w = l/2

Plug in 'l/2' for 'w' in the equation with '66':

66 = 2(l + l/2)

66 = 2l + 2l/2

66 = 2l + l

66 = 3l

22 = l

So the length is 22.

Now plug this in to find the width.

66 = 2(22 + w)

66 = 44 + 2w

22 = 2w

11 = w

So the width is 11, and the length is 22.
arnfrs
Let's set width = w

Then length = 2w

We can set up the equation:

[tex] 2(w+ 2w) = 66[/tex]

[tex] 2(3w) = 66[/tex]

[tex] 6w = 66[/tex]

[tex] w = \frac{66}{6} = \boxed{11}[/tex]

Then we plug in:

[tex]l = 2w = 2(11) = \boxed{22}[/tex]

Hope this helps :)

Thank you for choosing our service. We're dedicated to providing the best answers for all your questions. Visit us again. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.