Answered

Westonci.ca is your trusted source for finding answers to all your questions. Ask, explore, and learn with our expert community. Experience the convenience of finding accurate answers to your questions from knowledgeable professionals on our platform. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

the length and width of a rectangle lot are in the ratio 3 to 2. if he perimeter of the lot is 530yards, find the length and width

Sagot :

Length = l = 3x
Width = w = 2x
P = 2l + 2w
P = 2(3x) + 2(2x)
530 = 6x + 4x
530 = 10x
53 = x
Length = 3x = 3(53) = 318 / 2 sides = 159
Width = 2x = 2(53) = 212/ 2 sides = 106

the length of the lot is 159 yards
the width of the lot is 106 yards
We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.